225-49x^2=0

Solution for 225-49x^2=0 equation:

225-49x^2=0

a = -49; b = 0; c = +225;
Δ = b2-4ac
Δ = 02-4·(-49)·225
Δ = 44100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{44100}=210$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-210}{2*-49}=\frac{-210}{-98}
=2+1/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+210}{2*-49}=\frac{210}{-98}
=-2+1/7
$